KinematicsHard
Question
A particle is dropped from a height h . Another particle which was initially at a horizontal distance ‘d’ from the first is simultaneously projected with a horizontal velocity ‘u’ and the two particles just collide on the ground. The three quantities h. d and u are related to : -
Options
A.d2 = 
B.d2 = 
C.d = h
D.gd2 = u2h
Solution
Time to reach at ground = 
In this time horizontal displacement
d = u ×⇒ d2 = 
In this time horizontal displacement
d = u ×
⇒ d2 = Create a free account to view solution
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