KinematicsHard
Question
CE and DF are two walls of equal height (20 meter) from which two particles A and B of same mass are projected as shown in the figure. A is projected horizontally towards left while B is projected at an angle 37o (with horizontal towards left) with velocity 15 m/sec. If A always sees B to be moving perpendicular to EF, then the range of A on ground is :
Options
A.24 m
B.30 m
C.26 m
D.28 m
Solution
From given conditions : VA = VB cos37o 15.
= 12 m/sec.
∴ time of flight of A (t) =
= 2 sec.
⇒ Rang = VAt = 24 m
= 12 m/sec.∴ time of flight of A (t) =
= 2 sec.⇒ Rang = VAt = 24 m
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