Hard

Question

CE and DF are two walls of  equal height (20 meter)  from which  two particles A and B of same mass are projected as shown in the figure. A is projected horizontally towards left while B is projected at an angle 37o (with horizontal towards left) with velocity 15 m/sec. If  A  always sees B  to be moving perpendicular to EF,  then the range of A on ground is :

Options

A.24 m
B.30 m
C.26 m
D.28 m

Solution

From given conditions  : VA = VB cos37o 15. = 12 m/sec.
                   ∴  time of flight of A (t) = = 2 sec.
                   ⇒  Rang = VAt = 24 m
                  

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