KinematicsHard
Question
A body is released from the top of the tower H metre high. It takes t second to reach the ground. Where is the body after t/2 second of release?
Options
A.at 3H/4 metre from the ground
B.at H/2 metre from the ground
C.at H/6 metre from the ground
D.at H/4 metre from the ground
Solution
Applying S = ut = 
gt2 for the Ist case
H =gt2 .....(i)
Let H1 be the height after t/2 secs. So distance of fall + H = H1
H - H1 =
⇒ H - H1 =
gt2 .....(ii)
Dividing (i)and (ii),
⇒ 4H - 4H1 = H ⇒ H1 =
H
gt2 for the Ist caseH =
gt2 .....(i)Let H1 be the height after t/2 secs. So distance of fall + H = H1
H - H1 =
⇒ H - H1 =
gt2 .....(ii)Dividing (i)and (ii),
⇒ 4H - 4H1 = H ⇒ H1 =
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