Application of DerivativeHard
Question
The equation of tangent to the curve y = 1 - ex/2 at the point where it meets y-axis is-
Options
A.x + 2y = 0
B.2x + y = 0
C.x - y = 2
D.None of these
Solution
the equation of the tangent to curve
y = 1 - ex/2
it meets y-axis
0 = 1 - ex/2
x = 0
and y = 0
point (0, 0)
= - ex/2 × 
= - 
× e0/2 = - 
y - 0 =
(x - 0)
2y = -x
y = 1 - ex/2
it meets y-axis
0 = 1 - ex/2
x = 0
and y = 0
point (0, 0)
= - ex/2 × = - × e0/2 = - y - 0 =
(x - 0)2y = -x
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
The function f(x) is...If the polynomial equation anxn + an−1xn−1 + ... + a2x2 + a1x + a0 = 0 n positive integer, has two different...A balloon which always remains spherical, is being inflated by pumping in 900 cubic centimetres of gas per second. The r...The length of the subtangent at any point of the curve xmyn = am+n is proportional to-...A balloon which always remains spherical, is being inflated by pumping in 900 cubic centimetres of gas per second. The r...