Application of DerivativeHard
Question
The equation of tangent to the curve y = 1 - ex/2 at the point where it meets y-axis is-
Options
A.x + 2y = 0
B.2x + y = 0
C.x - y = 2
D.None of these
Solution
the equation of the tangent to curve
y = 1 - ex/2
it meets y-axis
0 = 1 - ex/2
x = 0
and y = 0
point (0, 0)
= - ex/2 × 
= - 
× e0/2 = - 
y - 0 =
(x - 0)
2y = -x
y = 1 - ex/2
it meets y-axis
0 = 1 - ex/2
x = 0
and y = 0
point (0, 0)
= - ex/2 × = - × e0/2 = - y - 0 =
(x - 0)2y = -x
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