Application of DerivativeHard
Question
The length of the subtangent at any point of the curve xmyn = am+n is proportional to-
Options
A.Ordinate
B.Abscissa
C.(Ordinate)n
D.(Abscissa)n
Solution
LST =
xmyn = am+n
yn =
n.yn-1 y1 = am+n
y′ = -
am+n 
LST =
LST =
× yn.xm.x
LST =
x
LST ∝ x
xmyn = am+n
yn =
n.yn-1 y1 = am+n
y′ = -
LST =
LST =
LST =
LST ∝ x
Create a free account to view solution
View Solution FreeMore Application of Derivative Questions
The equation of the normal to the curve x = at2, y = 2at at ′t′ point is -...If the tangent at any point on the curve x4 + y4 = c4 cuts off intercepts a and b on the coordinate axes, the value a...The slope of the normal to the curve x = a (θ - sinθ), y = a(1 - cosθ) at point θ = π/2 is -...At what point the tangent line to the curve y = cos(x + y), (-2π ≤ x ≤ 2π) is parallel to x + 2y =...The curve y = has...