FrictionMedium
Question
A conveyor bet is moving at a constant speed of 2 ms-1. A box is gently dropped on it. The coefficient of friction between them them is μ = 0.5. the distance that the box will move relative to belt before coming to rest on it, taking g = 10 ms-2 , is
Options
A.0.4 m
B.1.2 m
C.0.6 m
D.zero
Solution
Force of friction, f = μ mg
∴
= μg = 0.5 × 10 = 5 ms-1
Using v2 - u2 = 2as
02 - 22 = 2(- 5)× S ⇒ S = 0.4 m
∴
= μg = 0.5 × 10 = 5 ms-1Using v2 - u2 = 2as
02 - 22 = 2(- 5)× S ⇒ S = 0.4 m
Create a free account to view solution
View Solution FreeMore Friction Questions
A block A (5 kg) rests over another block B (3 kg) placed over a smooth horizontal surface. There is friction between A ...A chain of length L is placed on a horizontal surface as shown in figure. At any instant x is the length of chain on rou...A block of mass 1 kg is stationary with respect to a conveyer belt that is accelerating with 1 m/s2 upwards at an angle ...φ is the angle of the incline when a block of mass m just start slipping down. The distance covered by the block if...A block of mass m, lying on a rough horizontal plane, is acted upon by a horizontal force P and simultaneously by anothe...