FrictionMedium
Question
The two blocks, m = 10 kg and M = 50 kg are free to move as shown. The coefficient of static friction between the blocks is 0.5 and there is no friction between M and the ground. A minimum horizontal force F is applied to hold m against M that is equal to :
Options
A.100N
B.50N
C.240N
D.180N
Solution
(C) As m would slip in vertically downward direction, then mg = μN
∴ mg = μN
⇒ N =
= 200 Newton
Same normal force would accelerate M, thus aM =
= 4 m/s2
Taking (m + M) as system
F = (m + M). 4 = 240 N
∴ mg = μN
⇒ N =
= 200 Newton Same normal force would accelerate M, thus aM =
= 4 m/s2 Taking (m + M) as system
F = (m + M). 4 = 240 N
Create a free account to view solution
View Solution FreeMore Friction Questions
Two block A and B of masses 5 kg. and 3 kg. respectively rest on smooth horizontal surface with B over A. The coefficien...Having been paddled continuously on a horizontally road, the speed of a bicycle is increasing, the force of friction exe...Starting from rest, A flat car is given a constant acceleration ao = 2 m/s2. A cable is connected to a crate A of mass 5...Two masses m1 = 4 kg and m2 = 2kg are connected with an inextensible, massless string that passes over a frictionless pu...The upper half of an inclined plane with inclination φ is perfectly smooth while the lower half is rough. A body st...