Trigonometric EquationHard
Question
If √2 sec θ + tan θ = 1, then the general solution of θ -
Options
A.nπ + 3π/4
B.2nπ + π/4
C.2nπ - π/4
D.2nπ ± π/4
Solution
√2 sec θ + tan θ = 1
√2
= 1
⇒ √2 + sin θ = cos θ
cosθ - sinθ = √2 ⇒
cos θ - 
sin θ = 1
cos
= cos 0 ⇒ θ + 
= 2nπ ± 0
θ = 2nπ -
√2
= 1⇒ √2 + sin θ = cos θ
cosθ - sinθ = √2 ⇒
cos θ - sin θ = 1cos
= cos 0 ⇒ θ + = 2nπ ± 0 θ = 2nπ -
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