Trigonometric EquationMedium
Question
If √2 sec θ + tan θ = 1, then the general solution of θ -
Options
A.nπ + 3π/4
B.2nπ + π/4
C.2nπ - π/4
D.2nπ ± π/4
Solution
√2 sec θ + tan θ = 1
√2
= 1
⇒ √2 + sin θ = cos θ
cosθ - sinθ = √2 ⇒
cos θ - 
sin θ = 1
cos
= cos 0 ⇒ θ + 
= 2nπ ± 0
θ = 2nπ -
√2
= 1⇒ √2 + sin θ = cos θ
cosθ - sinθ = √2 ⇒
cos θ - sin θ = 1cos
= cos 0 ⇒ θ + = 2nπ ± 0 θ = 2nπ -
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
Number of values of ′θ′ such that 2 + cos2θ ≥ 3 where θ ∈ [-2π, 2π]...If f(x) = (2x - π)3 + 2x - cosx, then (f-1 (x)) at x = π is equal to -...Total number of integral values of ′n′ so that sin x (sin x + cos x) = n has at least one solution is-...If solution of the equation 3cos2θ - 2√3 sin θ cos θ - 3sin2 θ = 0 are nπ + π/r and ...The sum of the solutions of equation |cos2x| = | sin6x| in is -...