Trigonometric EquationHard
Question
If √2 sec θ + tan θ = 1, then the general solution of θ -
Options
A.nπ + 3π/4
B.2nπ + π/4
C.2nπ - π/4
D.2nπ ± π/4
Solution
√2 sec θ + tan θ = 1
√2
= 1
⇒ √2 + sin θ = cos θ
cosθ - sinθ = √2 ⇒
cos θ - 
sin θ = 1
cos
= cos 0 ⇒ θ + 
= 2nπ ± 0
θ = 2nπ -
√2
= 1⇒ √2 + sin θ = cos θ
cosθ - sinθ = √2 ⇒
cos θ - sin θ = 1cos
= cos 0 ⇒ θ + = 2nπ ± 0 θ = 2nπ -
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
The number of integers greater than 6000 that can be formed, using the digits 3,5,6,7 and 8 without repetition, is :...The number of solutions of the equation sin(ex) = 5x + 5-x is...The tangent to the curve y = ex drawn at the point (c, ec) intersects the line joining the points (c, - 1, ec-1) and (c ...For 0 cos2nφ, y =sin2nφ, z = cos2n φ sin2, then...In triangle ABC, 2ac sin (A - B + C) =...