Trigonometric EquationHard
Question
If tan6θ + 27 tan2θ = 3(1 + 11 tan4θ) is satisfied if θ is equals to :
Options
A.20o
B.15o
C.60o
D.40o
Solution
tan 3θ = 
= k(say)
(3 tan θ - tan3θ)2 = k2(1 - 3tan2θ)2
⇒ tan6θ + 3(3 + 2k2)tan2θ
= k2 + 3(3k2 + 2) tan47θ)
On comparing
k = ± √3
= k(say)(3 tan θ - tan3θ)2 = k2(1 - 3tan2θ)2
⇒ tan6θ + 3(3 + 2k2)tan2θ
= k2 + 3(3k2 + 2) tan47θ)
On comparing
k = ± √3
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