Differential EquationHard
Question
The solution of y5x + y - x
= 0 is -
Options
A.x4 / 4 + 1/ 5(x / y)5 = C
B.x5 / 5 + (1/ 4) (x / y)4 = C
C.(x / y)5 + x4 / 4 = C
D.(xy)4 + x5 / 5 = C
Solution
y5x + y - x
= 0
⇒
= y5
⇒
= 1
Let
= 1 ⇒ 
∴
= 1
⇒
= - 4
I.F. =
dx = e4 ln x = x4
so solution is t.x4 = - ∫4.x4 dx + c
⇒
= c
⇒
⇒
Let
∴
⇒
I.F. =
so solution is t.x4 = - ∫4.x4 dx + c
⇒
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