The solution of y5x + y - x = 0 is -

y5x + y - x = 0⇒ = y5⇒ = 1Let = 1 ⇒ ∴ = 1⇒ = - 4I.F. = dx = e4 ln x = x4so solution is t.x4 = - ∫4.x4 dx + c⇒ = c

Differential EquationMedium

Question

The solution of y⁵x + y - x = 0 is -

A.x⁴ / 4 + 1/ 5(x / y)⁵ = C

B.x⁵ / 5 + (1/ 4) (x / y)⁴ = C

C.(x / y)⁵ + x⁴ / 4 = C

D.(xy)⁴ + x⁵ / 5 = C

y⁵x + y - x = 0
⇒ = y⁵
⇒ = 1
Let = 1 ⇒
∴ = 1
⇒ = - 4
I.F. =

dx = e^{4 ln x} = x⁴
so solution is t.x⁴ = - ∫4.x⁴ dx + c
⇒ = c

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