Differential EquationHard

Question

The solution of the differential equation (1 + y²) + = 0, is

Options

A.xe^2tan⁻¹y = e^tan⁻¹y + k

B.(x − 2) = Ke^tan⁻¹y

C.2xe^tan⁻¹y = e^tan⁻¹y + K

D.xe^tan⁻¹y = tan⁻¹y + K

Solution

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