Differential EquationHard
Question
The solution of the differential equation (1 + x2) 
= x is-
= x is-Options
A.y = tan−1 x + c
B.y = − tan−1 x + c
C.y = 
loge (1 + x2) + c
loge (1 + x2) + cD.y = − loge (1 + x2) + c
loge (1 + x2) + c = x is- loge (1 + x2) + c loge (1 + x2) + c