Heat and Thermal ExpansionMedium
Question
Logarithms of readings of pressure and volume fo ran ideal gas plotted on a graph as shown in figure. By measuring the gradient, It can be shown that the gas may be : -
Options
A.Monoatomic and undergoing an adiabatic change.
B.Monotomic and undergoing an isothermal change
C.Diatomic and undergoing an adiabatic change
D.Triatomic and undergoing an isothermal change
Solution
PVγ = C; ln P + γlnV = lnC
⇒ lnP = - γlnV = lnC ⇒ Y = mx + c
m = - γ = -
= - 1.4
∴ The gas is diatomic
⇒ lnP = - γlnV = lnC ⇒ Y = mx + c
m = - γ = -
= - 1.4∴ The gas is diatomic
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