Atomic StructureHard
Question
A metal oxide has the formula Z2O3. It can be reduced by hydrogen to give free metal and water. 0.2 g of the metal oxide requires 12 mg of hydrogen for complete reduction. The atomic weight of the metal is
Options
A.52
B.104
C.26
D.78
Solution
Z2O3 + 3H2 → 2z + 3H2O
[0.2 g = 200 mg]
= 6 m mol
Since H2 used is 6 m mol, Z2O3 used should be 2 m mol.
Mol of Z2O3 =
= 2 × 10-3 moles
∴ Mw(Z2O3) = 100
∴ 2z + 16 × 3 = 100
z =
= 26
[0.2 g = 200 mg]
= 6 m mol
Since H2 used is 6 m mol, Z2O3 used should be 2 m mol.
Mol of Z2O3 =
= 2 × 10-3 moles∴ Mw(Z2O3) = 100
∴ 2z + 16 × 3 = 100
z =
= 26Create a free account to view solution
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