Heat and Thermal ExpansionHard
Question
One mole of an ideal monatomic gas is taken from A to C along the path ABC. The temperature of the gas at A is T0. For the process ABS : -
Options
A.Work done by the gas is RT0
B.Change in internal energy of the gas is 
RT0.
RT0.C.Heat absorbed by the gas is RT0.
RT0.D.Heat absorbed by the gas is 
RT0.
RT0.Solution
Work done = Area of ABC with V - axis
= P0(2V0 - 0) + 0 = P0V0 = nRT0 = RT0.
Change in internal energy = nCVᐃT
= 1 ×
R × (4T0 - T0) = 
RT0
∴ Heat absorbed = RT0 + RT0 = RT0.
= P0(2V0 - 0) + 0 = P0V0 = nRT0 = RT0.
Change in internal energy = nCVᐃT
= 1 ×
R × (4T0 - T0) = RT0∴ Heat absorbed =
RT0 + RT0 = RT0.Create a free account to view solution
View Solution FreeMore Heat and Thermal Expansion Questions
5g of steam at 100oC is mixed at 100oC is mixed with 10g of ice at 0oC. Chose correct alternative/s) :- (Given swater = ...A steel scale measure the length of a copper rod as l0 when both are at 20oC, which is the calibration temperature for t...An angular rod of same uniform material as shown in figure is conducting heat at a steady rate. The temperature gradient...Certain prefect gas is found to obey PVn = constant during adiabatic process. The volume expansion cofficient at tempera...If HC, HK and HF are heat required to rise the temperature of one gram of water by one degree in Celsius, Kelvin and Fah...