Heat and Thermal ExpansionHard
Question
One mole of an ideal monatomic gas is taken from A to C along the path ABC. The temperature of the gas at A is T0. For the process ABS : -
Options
A.Work done by the gas is RT0
B.Change in internal energy of the gas is 
RT0.
RT0.C.Heat absorbed by the gas is RT0.
RT0.D.Heat absorbed by the gas is 
RT0.
RT0.Solution
Work done = Area of ABC with V - axis
= P0(2V0 - 0) + 0 = P0V0 = nRT0 = RT0.
Change in internal energy = nCVᐃT
= 1 ×
R × (4T0 - T0) = 
RT0
∴ Heat absorbed = RT0 + RT0 = RT0.
= P0(2V0 - 0) + 0 = P0V0 = nRT0 = RT0.
Change in internal energy = nCVᐃT
= 1 ×
R × (4T0 - T0) = RT0∴ Heat absorbed =
RT0 + RT0 = RT0.Create a free account to view solution
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