Chemical EquilibriumHard
Question
For the reaction X ⇋ 2Y and Z ⇋ P + Q occuring at two different pressure P1 and P2, respectively. The ratio of the two pressure is 1 : 3. What will be the ratio of equilibrium constant, if the degree of dissociation of X and Z are equal.
Options
A.1 : 36
B.1 : 12
C.1 : 9
D.2 : 3
Solution
for reaction X ⇋ 2Y
Initial 1 0
At equilibrium 1 - α 2α
Total moles = 1 - α + 2α = 1 + α
Px =
P1; PY =
P1
∴ Kp1 =
..... (ii)
Similarly for X ⇋ P + Q
Initial 1 0 0
At equilibrium 1 - α 2α α
Total moles = 1 - α + α + α = 1 + α
PZ =
P2; PQ =
P2; PP = 
Kp2 =
...... (i)
Dividing equations (i) and (ii), we get,
(given)
∴
Initial 1 0
At equilibrium 1 - α 2α
Total moles = 1 - α + 2α = 1 + α
Px =
∴ Kp1 =
Similarly for X ⇋ P + Q
Initial 1 0 0
At equilibrium 1 - α 2α α
Total moles = 1 - α + α + α = 1 + α
PZ =
Kp2 =
Dividing equations (i) and (ii), we get,
∴
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