Heat and Thermal ExpansionHard

Question

Figure shows the adiabatic curve on log-log scale performed on a ideal gas. The gas must be :-

Options

A.Monoatomic
B.Diatomic
C.A mixture of monoatomic and diatomic
D.A mixture of diatomic and polyatomic

Solution

For adiabatic process TVγ-1 = constant
 log T + (γ + 1) log V = constant ⇒ slope  = - (γ + 1) = - ⇒ γ =
For monoatomic gas γ = γ = ; For diatomic gas γ = As < γ = <
Hence, the gas must be a mixture of monoatomic & diatomic gas.

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