Heat and Thermal ExpansionHard
Question
Figure shows the adiabatic curve on log-log scale performed on a ideal gas. The gas must be :-
Options
A.Monoatomic
B.Diatomic
C.A mixture of monoatomic and diatomic
D.A mixture of diatomic and polyatomic
Solution
For adiabatic process TVγ-1 = constant
log T + (γ + 1) log V = constant ⇒ slope = - (γ + 1) = -
⇒ γ = 
For monoatomic gas γ = γ = 
; For diatomic gas γ = 
As < γ = <
Hence, the gas must be a mixture of monoatomic & diatomic gas.
log T + (γ + 1) log V = constant ⇒ slope = - (γ + 1) = -
⇒ γ = For monoatomic gas γ =
γ = ; For diatomic gas γ = As < γ = < Hence, the gas must be a mixture of monoatomic & diatomic gas.
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