Chemical Kinetics and Nuclear ChemistryHard
Question
Number of natural life times (Tav) required for a first-order reaction to achieve 99.9% level of completion is :
Options
A.2.3
B.6.9
C.9.2
D.0.105
Solution
We know
k =
99.9% completion
a = 100
a × x = (100 - 99.90) = .10
Then t =
t = 2.303 × 3 ×
t = 6.9 × tav
k =
99.9% completion
a = 100
a × x = (100 - 99.90) = .10
Then t =
t = 2.303 × 3 ×
t = 6.9 × tav
Create a free account to view solution
View Solution FreeTopic: Chemical Kinetics and Nuclear Chemistry·Practice all Chemical Kinetics and Nuclear Chemistry questions
More Chemical Kinetics and Nuclear Chemistry Questions
Identify compound which give fastest dehydration ?...The half-life for the first-order reaction H2O2(aq) → H2O(l) + ½O2(g) is 30 minutes. If the volume of O2(g) collected is...In compounds of type ECl3 where E = B, P. As or Bi, the angles Cl − E − Cl for different R in order-...Hydrogen bomb is based on the principle of...The compound A decomposed (A → product) by first order kinetics. If the concentration of A dropped from 0.1 M to 0...