ElectrochemistryHard
Question
A current is passed through 500 mL of an aqueous solution of CaI2. After sometime, it is observed that 50 millimoles of I2 have been formed. Which of the following statements is(are) correct ?
Options
A.The number of faradays of charge passed through the solution is 0.10 F.
B.The volume of dry H2 at STP that has been formed during electrolysis is 1120 mL.
C.The pH of the solution is nearly 0.7.
D.The mass of calcium produced is 2.0 g.
Solution
CaI2(aq): Cathode Ca2+, H+
+
Anode I- OH-
×
a.
b. Also, mmoles of H2 =
× number of mF
=
× 100 = 50 VH2 at STP
= 50 × 22.4 ml = 1120 mL
c. 100 mmoles OH- left
⇒ [OH-] =
= 0.2
⇒ pOH = - log 0.2 = 0.7
⇒ pH = 13.3
+
Anode I- OH-
×
a.
b. Also, mmoles of H2 =
× number of mF=
× 100 = 50 VH2 at STP= 50 × 22.4 ml = 1120 mL
c. 100 mmoles OH- left
⇒ [OH-] =
= 0.2⇒ pOH = - log 0.2 = 0.7
⇒ pH = 13.3
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