ElectrochemistryHard

Question

A line L : y = mx + 3 meets y - axis at E(0,3) and the arc of the parabola y2 = 16x, 0 ≤ y ≤ 6 at the point F(x0,y0). The tangent to the parabola at F(x0,y0) intersects the y-axis at G(0,y1). The slope m of the line L is chosen such that the area of the triangle EFG has a local maximum.
Match List-I with List-II and select the correct answer using the code given below the lists.
       List-I                                             List-II
P.     m =                                               1.   1/2
Q.    Maximum  area  of ᐃEFG is     2.    4
R.    y0 =                                               3.    2
S.    y1 =                                               4.    1

Options

A.P → 4, Q → 1, R → 3, S → 2
B.P → 3, Q → 4, R → 1, S → 2
C.P → 1, Q → 3, R → 2, S → 4
D.P → 1, Q → 3, R → 4, S → 2

Solution

Let F(4t2, 8t)
where

          


ᐃ = (6t2 - 8t3)




y0 = 8t = 4 & y1 = 4t = 2

Create a free account to view solution

View Solution Free
Topic: Electrochemistry·Practice all Electrochemistry questions

More Electrochemistry Questions

Electrode potential data are given below.Fe3+ (aq) + e- → Fe2+ (aq); Eo = + 0.77 Al3+ (aq) + 3e- → Al (s); E...A solution containing one mol per litre each of Cu(NO3)2, AgNO3, Hg(NO3)2 and Mg(NO3)2 is being electrolysed by using in...Rusting of iron is catalyzed by...The efficiency of a fuel cell is 80% and the standard heat of reaction is -300kJ. The reaction involves two electrons in...MnO4- + 8H+ + 5e- → Mn2+ + 4H2O, If H+ concentration is decreased from 1 M to 10-4 M at 25oC, where as concentrati...