ElectrochemistryHard
Question
Electrode potential data are given below.
Fe3+ (aq) + e- → Fe2+ (aq); Eo = + 0.77
Al3+ (aq) + 3e- → Al (s); Eo = - 1.66 V
Br2 (aq) + 2e- → 2Br- (aq) ; Eo = + 1.08 V
Based one the data given above, reducing power of Fe2+, Al and Br- will increase in the order :
Fe3+ (aq) + e- → Fe2+ (aq); Eo = + 0.77
Al3+ (aq) + 3e- → Al (s); Eo = - 1.66 V
Br2 (aq) + 2e- → 2Br- (aq) ; Eo = + 1.08 V
Based one the data given above, reducing power of Fe2+, Al and Br- will increase in the order :
Options
A.Br- < Fe2+ < Al
B.Fe2+ < Al < Br-
C.Al < Br- < Fe2+
D.Al < Fe2+ < Br-
Solution
Lowest S.R.P., highest reducing power.
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