ElectrochemistryHard
Question
Zn + Cu2+(aq) ⇋ Cu + Zn2+(aq)
Reaction quotient is Q =
. Variation of Ecell with log Q is of the type with OA = 1.10 V. Ecell will be 1.1591 V when

Reaction quotient is Q =

Options
A.[Cu2+] / [Zn2+] = 0.01
B.[Zn2+] / [Cu2+] = 0.01
C.[Zn2+] / [Cu2+] = 0.1
D.[Zn2+] / [Cu2+] = 1
Solution
Ecell = E-cell -
log
From line OA = E-cell = 1.10 V
= 10-2 M, then Ecell = 1.1591 V
From line OA = E-cell = 1.10 V
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The Ecell for a given cell is 1.2346 and 1.2340 V at 300 K and 310 K, respectively. Calculate the change in entropy duri...In which of the following molecules π - electron density in ring is minimum :...A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams of copper can be liberated by the same curren...The emf of Daniel cell at 298 K is E1Zn|ZnSO4(0.01M)||CuSO4(1.0M)|Cu When the concentration of ZnSo4 is 1.0 M and that o...Fe is reacted with 1.0 M HCl. Eo for Fe / Fe2+ = + 0.34 V. The correct observation(s) regarding this reaction is/are :...