Solid StateHard
Question
In a hypothetical solid, C atoms are found to form cubical close-packed lattice. A atoms occupy all tetrahedral voids and B atoms occupy all octahedral voids.
A and B atoms are of appropriate size, so that there is no distortion in the ccp lattice of C atoms. Now if a plane as shown in the following figure is cut, then the cross section of this plane will look like
A and B atoms are of appropriate size, so that there is no distortion in the ccp lattice of C atoms. Now if a plane as shown in the following figure is cut, then the cross section of this plane will look like
Options
A.
B.
C.
D.
Solution
From figure it is clear 4 corners and 2 face centers lie on the shaded plane. Therefore, there will be six C atoms, and atoms (marked A) in TVs do not touch other.
Fig. (A) is not possible; four atom marked C.
Fig. (B) is not possible, atoms A in TVs are not shown in figure.
Fig. (C) is possible, since atoms A in TVs are not touching each other.
Fig. (D) is not possible, since atoms A in TVs are touching each other.
Fig. (A) is not possible; four atom marked C.
Fig. (B) is not possible, atoms A in TVs are not shown in figure.
Fig. (C) is possible, since atoms A in TVs are not touching each other.
Fig. (D) is not possible, since atoms A in TVs are touching each other.
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