Work, Power and EnergyHard
Question
A position dependent force,
F = 7 - 2x + 3x2 N,
acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done (in joule) is :-
F = 7 - 2x + 3x2 N,
acts on a small body of mass 2 kg and displaces it from x = 0 to x = 5m. The work done (in joule) is :-
Options
A.70
B.270
C.35
D.135
Solution
F = (7 - 2x + 3x2) N
x = 5
W =
Fdx
W =
(7 - 2x + 3x2)dx
W = [7x - x2 + x]05
W = [(35 - 25 + 125) - 0 ]
W = 135 J
x = 5
W =
FdxW =
(7 - 2x + 3x2)dxW = [7x - x2 + x]05
W = [(35 - 25 + 125) - 0 ]
W = 135 J
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