Work, Power and EnergyHard

Question

A sample of 0.1 g of water at 100oC and normal pressure (1.013 ×105 Nm–2) requires 54 cal of heat energy to convert to steam at 100oC. If the volume
of the steam produced is 167.1 cc, the change in internal energy of the sample, is :-

Options

A.

104.3 J

B.

208.7 J

C.

42.2 J

D.

84.5 J

Solution

∆Q = 54 cal = 54 × 4.18 joule = 225.72 joule
∆W = P[Vsteam – Vwater] [For water 0.1 gram=0.1 cc]
= 1.013 × 105[167.1 × 10–6 – 0.1 × 10–6] joule
= 1.013 × 167 × 10–1 = 16.917 joule
By FLOT
⇒∆U = ∆Q – ∆W = 225.72 – 16.917
∆U = 208.8 joule

Create a free account to view solution

View Solution Free
Topic: Work, Power and Energy·Practice all Work, Power and Energy questions

More Work, Power and Energy Questions

Two masses of 1 gm an 4 gm are moving with the same kinetic energy. The ratio of their linear momentum will be -...The unit of the co-efficient of restitution is -...A crane lifts 300 kg weight from earth′s surface upto a height of 2m in 3 seconds. The average power generated by ...A pendulum bob of mass m is suspended at rest. A constant horizontal force F = mg /2 starts acting on it. The maximum an...Potential at a point x is 5 V and at a point y is -5V. A proton is moving towards x from y, then...