Work, Power and EnergyMedium
Question
A box of mass m is initially at rest on a horizontal force of mg / 2 is applied to the box directed to the right. the coefficient of friction of the surface changes with the distance pushed as μ = μ0x where x is the distance from the initial location. For what distance is the box pushed initial it comes to rest again ?
Options
A.
B.
C.
D.
Solution
Net change in kinetic energy = 0 ⇒ net work W = 0
W = ∫ dW = ∫ Fdx - ∫ μNdx =
x - mgμ0 
xdx = 0 ⇒ =
W = ∫ dW = ∫ Fdx - ∫ μNdx =
x - mgμ0 xdx = 0 ⇒ = Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
Three different objects m1, m2 and m3 are allowed to fall from rest and from the same point O along three different fric...A hammer of mass M strikes a nail of mass m with velocity of v ms-1 and drives it ′a′ metre into fixed block...Two pith balls carrying equal charges are suspended from a common point by strings of equal length, the equilibrium sepa...The amount of work done in stretching a spring from a stretched length of 10 cm to a stretched length of 20 cm is-...A network of four capacitors of capacity equal to C1 = C,C = 2C,C3 = 3C and C4 = 4C are conducted to a batter as shown i...