Work, Power and EnergyHard
Question
A box of mass m is initially at rest on a horizontal force of mg / 2 is applied to the box directed to the right. the coefficient of friction of the surface changes with the distance pushed as μ = μ0x where x is the distance from the initial location. For what distance is the box pushed initial it comes to rest again ?
Options
A.
B.
C.
D.
Solution
Net change in kinetic energy = 0 ⇒ net work W = 0
W = ∫ dW = ∫ Fdx - ∫ μNdx =
x - mgμ0 
xdx = 0 ⇒ =
W = ∫ dW = ∫ Fdx - ∫ μNdx =
x - mgμ0 xdx = 0 ⇒ = Create a free account to view solution
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