Photoelectric EffectHard
Question
Light from a hydrogen discharge tube is incident on the cathode of a photoelectric cellthe work function of the cathode surface is 4.2 eV. In order to reduce the photocurrent to zero the voltage of the anode relative to the cathode must be made :-
Options
A.- 4.2 V
B.-9.4 V
C.-17.8 V
D.+9.4 V
Solution
ev0 = E - φ
= 13.6 - 4.2
ev0 = 9.4 ev
v0 = - 9.4v
= 13.6 - 4.2
ev0 = 9.4 ev
v0 = - 9.4v
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