A wooden block of mass 10 gram is dropped from the top of a tower of height 100 m. Simultaneausly a

Question

A wooden block of mass 10 gram is dropped from the top of a tower of height 100 m. Simultaneausly a bullet of mass 10 g is fired from the foot of the tower vertically upwards with a velocity of 100 m/s. If the bullet is embedded in it, how high will the block rise above the tower before it starts falling? (g = 10 m/s2) :-

Accepted Answer

The bullet and block will meet after time,
t = = 1sec.
distance travelled by block during this time
S - gt² = 5m
distance travelled by bullet,
     100 - 5 = 95 m
Velocity of bullet before collision
⇒ v1 = u - gt
     = 100 - 10 × 1 = 90 m/sec
Velocity of block before collision
⇒ v₂ = gt = 10 m/sec
      m₁v₁ + m₂v₂ = (m₁+ m₂)v
⇒    v = = 40m / sec
max. height reached by block = = 80 m
from the top of tower = 80 - 5 = 75 m

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