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Question

A positive point charge is placed at P in front of an earthed metal sheet. Q & R are two points between P & S(on the rod) as shown in figure. If the electric field strength at Q & R are respectively EQ & ER and potential at Q & R are respectively VQ & VR . Then-
         

Options

A.EQ = ER
B.EQ < ER
C.VQ > VR
D.VQ < VR

Solution

       
As we are are moving away from P toward sheet S spacing between electric lines of force is increasing.
∴ ER < EQ In direction of electric field potential decreases.
∴ VR < VQ

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