Atomic StructureMedium
Question
The I.P. of an atom is 16 eV. What is the value of first excitation potential :
Options
A.10.2 eV
B.12 eV
C.14 eV
D.16 eV
Solution
E∞ - E1 = 16 eV ⇒ E1 = - 16eV
E2 =
= - 4eV
Ist excitation potential = E2 - E1
= - 4eV - (-16eV)
= 12 eV
E2 =
= - 4eVIst excitation potential = E2 - E1
= - 4eV - (-16eV)
= 12 eV
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