KTGHard
Question
The specific heats of argon at constant pressure and constant volume are 525 J/kg and 315 J/kg respectively. Its density at NTP will be :-
Options
A.1.77 kg/m3
B.0.77 kg/m3
C.1.77 gm/m3
D.0.77 gm/m3
Solution
Cp - Cv = 
525 - 315 = 210 =
= 210 × 273
ρ = 1.77 kg/m3
525 - 315 = 210 =
= 210 × 273ρ = 1.77 kg/m3
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