Chemical BondingMedium
Question
The first ionisation energy of Na, NO, Xe and O2 follows the order Na < NO < Xe = O2 .O2 reacts with powerful oxidising agent (PtF6) to yield O2+[PtF6]-. If PtF6 is allowed to react with other mentioned species then the product is/are
Options
A.Only Na+[PtF6]-
B.Only NO+[PtF6]-
C.Only Xe[PtF6]-
D.Na+[PtF6]-, NO+[PtF6]-, Xe+[PtF]-
Solution
As PtF6 is a powerful oxidizing agent hence.
Na + PtF6 → Na+[PtF6]- ;
NO + PtF6 → NO+[PtF6]-
Xe + PtF6 → Xe+[PtF6]-
Na + PtF6 → Na+[PtF6]- ;
NO + PtF6 → NO+[PtF6]-
Xe + PtF6 → Xe+[PtF6]-
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