Trigonometric EquationHard
Question
is -Options
A.0
B.
+ tan-1(2)
+ tan-1(2)C.cot-1(3)
D.
Solution
Tr = tan-1 
= tan-1
Tr = tan-1((r + 1) (r + 3)) - tan-1(r(r + 2))
T1 = tan-1(8) - tan-1(3)
T2 = tan-1(15) - tan-1(8)
|
|
Tn = tan-1((r + 1) (r + 3)) - tan-1(r(r + 2))
Sn = cot-13
= tan-1
Tr = tan-1((r + 1) (r + 3)) - tan-1(r(r + 2))
T1 = tan-1(8) - tan-1(3)
T2 = tan-1(15) - tan-1(8)
|
|
Tn = tan-1((r + 1) (r + 3)) - tan-1(r(r + 2))
Sn = cot-13
Create a free account to view solution
View Solution FreeMore Trigonometric Equation Questions
A curve which passes through origin and satisfies(y + sinx . cos2(xy))sec2(xy)dx + (xsec2(xy) + siny)dy = 0 will be -...For any real value of θ ≠ π the value of the expression y = is-...The equation of the normal to the curve y = x + sin x cos x at x = π/2 is-...Find minimum and maximum value of 3cosx + 5sin(x - π/6)...A bird is sitting on the top of a vertical pole 20 m high and its elevation from a point O on the ground is 45o. It flie...