ThermodynamicsHard
Question
For an ideal gas, consider only P-V work in going from an initial state X to the final state Z. The final stateZ can be reached by either of the two paths shown in the figure. Which of the following choice(s) is(are)correct? [Take ᐃS as change in entropy and w as work done]
Options
A.ᐃSx→z = ᐃSx→y + ᐃSy→z
B.Wx→z = Wx→y + Wy→z
C.Wx→y→z = Wx→y
D.ᐃSx→y→z = ᐃSx→y
Solution
ᐃSx→z = ᐃSx→y + ᐃSY→Z [entropy S is a state function, hence additive]
WX→Y→Z = WX→Y (work done in Y → Z is zero as it is an isochoric process)
WX→Y→Z = WX→Y (work done in Y → Z is zero as it is an isochoric process)
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
A real gas is subjected to an adiabatic process from (2 bar, 40 L, 300 K) to (4 bar, 30 L, 300 K) against a constant pre...One mole of an ideal gas with the adiabatic exponent ‘$\gamma$’ goes through a polytropic process as a result of which t...Oxygen gas weighing 64 g is expanded from 1 atm to 0.25 atm at 30°C. What is the entropy change, assuming the gas to be ...For the reaction, , graph is plotted as shown below. Identify correct statements.A. Standard free energy change for the ...What is the change in internal energy when a gas contracts from 325 ml to 125 ml at a constant pressure of 2 bar, while ...