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Question
The Henry's law constant $\left( K_{H} \right)$ values of three gases $(A,B,C)$ in water are $145,2 \times 10^{- 5}$ and 35 kbar, respectively. The solubility of these gases in water follows the order:
Options
A.$A > C > B$
B.A $>$ B $>$ C
C.B $>$ A $>$ C
D.$B > C > A$
Solution
Sol. [Key Concept: Henry law constant and gas solubility]
Using the NCERT convention p = Kₕx, the dissolved gas mole fraction is x = p/Kₕ. At the same temperature and gas partial pressure, a smaller Kₕ means greater solubility.
Since 2 × 10⁻⁵ < 35 < 145 kbar,
the solubility order is B > C > A, option (4).
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