Coordination CompoundMedium
Question
Match List I with List II.
| List I (Complex) | List II (Type of isomerism) |
|---|---|
| A. $\left\lbrack Co\left( {NH}_{3} \right)_{5}\left( {NO}_{2} \right) \right\rbrack{Cl}_{2}$ | I. Solvate isomerism |
| B. $\left\lbrack Co\left( {NH}_{3} \right)_{5}\left( {SO}_{4} \right) \right\rbrack Br$ | II. Linkage isomerism |
| C. $\left\lbrack Co\left( {NH}_{3} \right)_{6} \right\rbrack\left\lbrack Cr(CN)_{6} \right\rbrack$ | III. Ionization isomerism |
| D. $\left\lbrack Co\left( H_{2}O \right)_{6} \right\rbrack{Cl}_{3}$ | IV. Coordination isomerism |
Choose the correct answer from the options given below:
Options
A.A-I, B-IV, C-III, D-II
B.A-II, B-IV, C-III, D-I
C.A-II, B-III, C-IV, D-I
D.A-I, B-III, C-IV, D-II
Solution
Sol. [Key Concept: Isomerism of coordination compounds]
[Co(NH₃)₅(NO₂)]Cl₂ can show linkage isomerism through N or O binding of NO₂⁻ (A–II). [Co(NH₃)₅SO₄]Br can show ionisation isomerism by exchange of coordinated SO₄²⁻ and counterion Br⁻ (B–III). [Co(NH₃)₆][Cr(CN)₆] can show coordination isomerism by redistribution of ligands between the complex ions (C–IV). [Co(H₂O)₆]Cl₃ belongs to the familiar hydrate or solvate isomer series (D–I). Hence, option (3).
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