Chemical BondingMedium
Question
Match List I with List II.
| List I (Compound) | List II(Shape/geometry) |
|---|---|
| A. ${NH}_{3}$ | I. Trigonal Pyramidal |
| B. ${BrF}_{5}$ | II. Square Planar |
| C. ${XeF}_{4}$ | III. Octahedral |
| D. ${SF}_{6}$ | IV. Square Pyramidal |
Choose the correct answer from the options given below:
Options
A.A-III, B-IV, C-I, D-II
B.A-II, B-III, C-IV, D-I
C.A-I, B-IV, C-II, D-III
D.A-II, B-IV, C-III, D-I
Solution
Sol. [Key Concept: Molecular shapes from VSEPR]
${NH}_{3} \Rightarrow sp^{3}$ hybridised with 1 lone pair. Structure will be Trigonal Pyramidal.
${BrF}_{5} \Rightarrow sp^{3}d^{2}$ hybridised with 1 lone pair. Structure will be Square Pyramidal.
${XeF}_{4} \Rightarrow sp^{3}d^{2}$ with two lone pairs. Structure will be Square Planar.
$SF_{6} \Rightarrow sp^{3}d^{2}$ with no lone pair. Structure will be Octahedral.
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