d and f-Block ElementsMedium

Question

The $E^{\circ}$ value for the ${Mn}^{3 +}/{Mn}^{2 +}$ couple is more positive than that of ${Cr}^{3 +}/{Cr}^{2 +}$ or ${Fe}^{3 +}/{Fe}^{2 +}$ due to change of

Options

A.$d^{4}$ to $d^{5}$ configuration
B.$d^{3}$ to $d^{5}$ configuration
C.$d^{5}$ to $d^{4}$ configuration
D.$d^{5}$ to $d^{2}$ configuration

Solution

Sol. [Key Concept: Stability of Mn²⁺ and reduction potential]

$E_{{Mn}^{3 +}/{Mn}^{2 +}}^{\circ} > E_{{Cr}^{3 +}/{Cr}^{2 +}}^{\circ}$ or $E_{{Fe}^{3 +}/{Fe}^{2 +}}^{\circ}$

Electronic configuration of ${Mn}^{3 +} = \lbrack Ar\rbrack 3d^{4}$

Electronic configuration of ${Mn}^{2 +} = \lbrack Ar\rbrack 3d^{5}$

Electronic configuration of ${Cr}^{3 +} = \lbrack Ar\rbrack 3d^{3}$

Electronic configuration of ${Cr}^{2 +} = \lbrack Ar\rbrack 3d^{4}$

As ${Mn}^{3 +}$ from $d^{4}$ configuration goes to more stable $d^{5}$ configuration (Half filled), due to more exchange energy in $d^{5}$ configuration

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