SHMMedium
Question
The displacement of a particle varies according to the relation x = 3 sin 100 t + 8 cos250 t. Which of the following is / are about this motion.
Options
A.the motion of the particle is not S.H.M
B.the amplitude of the S.H.M. of the particle is 5 units
C.the amplitude of the resultant S.H.M is √73 units
D.they maximum displacement of the origin is 9 units
Solution
x = 3 sin 100t + 8 cos2 50t
= 3sin (100t) + 4(1 + cos 100t)
= 4 + 5sin (100t + 37o)
Amplitude = 5
Maximum = 5
maximum displacement = 4 + 5 = 9 cm
= 3sin (100t) + 4(1 + cos 100t)
= 4 + 5sin (100t + 37o)
Amplitude = 5
Maximum = 5
maximum displacement = 4 + 5 = 9 cm
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