Logic gateMedium
Question
A logic circuit provides the output $Y$ as per the following truth table :
| $$A$$ | $$B$$ | $$Y$$ |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
The expression for the output $Y$ is :
Options
A.$\bar{B}$
B.$B$
C.$A \cdot B + \bar{A}$
D.$A \cdot \bar{B} + \bar{A}$
Solution
Sol. [Key Concept: Deducing the logic circuit from its truth table]
| $$A$$ | $$B$$ | $$Y$$ |
|---|---|---|
| 0 | 0 | 1 |
| 0 | 1 | 0 |
| 1 | 0 | 1 |
| 1 | 1 | 0 |
According to given truth table, output is independent on value of $A$
∴ Output $Y = \bar{B}$
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