Question

Sol. [Key Concept: AC through a capacitor — capacitive reactance]

Capacitive Reactance $X_{C} = \frac{1}{\omega C} = \frac{1}{2\pi fC} = \frac{1}{2 \times 3.14 \times 50 \times 10 \times 10^{- 6}}$

$$= \frac{1000}{3.14}$$

$$\begin{matrix} & V_{rms} = 210\text{ }V \\ & i_{rms} = \frac{V_{rms}}{X_{C}} = \frac{210}{X_{C}} \end{matrix}$$

$$\begin{matrix} \text{~}\text{Peak current}\text{~} & \ = \sqrt{2}i_{rms} = \sqrt{2} \times \frac{210}{1000} \times 3.14 = 0.932 \\ & \ \simeq 0.93\text{ }A \end{matrix}$$