ElectroMagnetic InductionHard
Question
A bulb is rated of 100 V, 100W, it can be treated as a resistor. Find out the inductance of an inductor (called choke coil) that should be connected in series with the bulb to operate the bulb at its rated power with the help of an ac source of 200V and 50 Hz
Options
A.
B.100 H
C.
D.
Solution
P = 
⇒ R = 
= 100Ω
with AC source
P =
R ⇒ Z = 200Ω
Z2 = R2 + ω2L2 ⇒ L =
⇒ R = = 100Ωwith AC source
P =
R ⇒ Z = 200ΩZ2 = R2 + ω2L2 ⇒ L =
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