Question
Length of the stem at time 0 is 20 cm. The arithmetic growth rate is 30 cm per day. What is the length of the stem at the end of the $7^{\text{th}\text{~}}$ day?
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Solution
Sol. [Key Concept: Arithmetic growth — Lₜ = L₀ + rt]
Arithmetic growth can be expressed as:
$$\begin{matrix} & L_{t} = L_{0} + rt\ \ \left\lbrack \text{~}\text{where,}\text{~}L_{t} = \text{~}\text{length at time '}\text{~}t\text{~}\text{',}\text{~}L_{0} = \text{~}\text{Length at time 'zero',}\text{~}r = \text{~}\text{growth rate}\text{~} \right.\ \text{~}\text{]}\text{~} \\ & \begin{matrix} L_{7\text{~}\text{th day}\text{~}} \Rightarrow 20 + 30 \times 7 \\ \ \ \ \ \ \ \ \ \ \ \ \Rightarrow 20 + 210 \\ \ \ \ \ \ \ \ \ \Rightarrow 230\text{ }cm \end{matrix} \end{matrix}$$
The length of the stem at the end of $7^{\text{th}\text{~}}$ day is 230 cm.
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