ElectrostaticsMedium
Question
A point charge $Q$ is placed inside a cavity within a solid isolated conducting sphere. Consider points $A,B$ and $C$ as shown in the figure, where the magnitudes of the electric fields are $E_{A},E_{B},E_{C}$, respectively. The points $B$ and $C$ are at the same distance from the center of the solid sphere. The correct option is :
Options
A.$E_{A} = 0,E_{B} > E_{C}$
B.$E_{A} \neq 0,E_{B} < E_{C}$
C.$E_{A} = 0,E_{B} = E_{C}$
D.$E_{A} \neq 0,E_{B} = E_{C}$
Solution
Sol. [Key Concept: Charge in a conductor's cavity — induced charges]
Due to charge $Q$ present inside cavity, $E_{A} \neq 0$
Charge distribution will be uniform on the outer surface of conducting sphere,
Since $B$ and $C$ are at same distance from centre of sphere,
EB = EC (Due to electrostatic shielding)
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