ElectrostaticsHard
Question
An oil drop of mass M is found floating freely between the plates of a parallel plate condenser (which consists of two large metallic plates having equal and opposite charges), the plates being horizontal and the lower plate carrying a charge +Q. The area of each plate is A and the distance of separation between them is D. The charge on the oil drop must be (g is the acceleration due to gravity)
Options
A.
B.
C.
D.
Solution
Let the charge on oil drop be q, so in equilibrium :
qE = Mg
⇒ q =
= Mg⇒ q =
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