A thin horizontal disc is rotating about a vertical axis passing through its fixed centre $O$. Its a

Question

A thin horizontal disc is rotating about a vertical axis passing through its fixed centre $O$. Its angular momentum is $L_{A}$ and $L_{B}$ computed about points $A$ and $B$, respectively, with $OB = 2 \times OA$. The value of $\frac{L_{A}}{L_{B}}$ is:

Accepted Answer

Sol. [Key Concept: Rotational dynamics of a rotating disc]$\overrightarrow{L} = \overrightarrow{r} 	imes \overrightarrow{P} + I_{cm}\overrightarrow{\omega}$$\overrightarrow{P} = 0$ for both axisSo ${\overrightarrow{L}}_{A} = {\overrightarrow{L}}_{B} = I_{cm}\overrightarrow{\omega}$$$\frac{{\overrightarrow{L}}_{A}}{{\overrightarrow{L}}_{B}} = 1$$

Question

Options

Solution

More Rotational Motion Questions