Rotational MotionMedium
Question
A ring of radius 3a is fixed rigidly on a table. A small ring whose mass is m and radius a, rolls without slipping inside it as shown in the figure. The small ring is released from position A. When it reaches at the lowest point, the speed of the centre of the ring at that time would be -
Options
A.
B.
C.
D.
Solution
From the energy conservation
mg × 2a =
v2 = 2ag ⇒ v =
mg × 2a =
v2 = 2ag ⇒ v =
Create a free account to view solution
View Solution FreeMore Rotational Motion Questions
For rotational motion, the Newton′s second law of motion is indicated by :-...Ratio of masses and radii of two circular rings are 1 : 2 and 2 : 1 respectively then ratio of moment of inertia will be...Four point masses, of a value m are placed at the corners of a square ABCD of side l.The moment of interia of this syste...A uniform disc of radius R lies in the x-y plane with its centre at the origin. Its moment of inertia about z axis is eq...A sphere S rolls without slipping, moving with a constant speed on a plank P. The friction between the upper surface of ...