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Question

In potash alum, the ratio of $K^{+}$and ${SO}_{4}^{2 -}$ ions is

Options

A.2 : 3
B.3 : 2
C.1 : 2
D.2 : 1

Solution

Sol. [Key Concept: Potash alum — K⁺ : SO₄²⁻ ratio from its formula]

Potash alum

$$K_{2}{SO}_{4} \cdot {Al}_{2}\left( {SO}_{4} \right)_{3} \cdot 24H_{2}O$$

No. of $K^{+} = 2$

No. of ${SO}_{4}^{2 -} = 4$

Ratio $\frac{K^{+}}{{SO}_{4}^{2 -}} = \frac{2}{4} = \frac{1}{2}$

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