d and f-Block ElementsMedium
Question
The lanthanide ion having four unpaired electrons is
(Given: Atomic numbers of $Ce = 58,Nd = 60,\text{ }Tb = 65$ and $Ho = 67$ )
Options
A.${Tb}^{3 +}$
B.${Ho}^{3 +}$
C.${Nd}^{3 +}$
D.${Ce}^{3 +}$
Solution
Sol. [Key Concept: Unpaired electrons from the f-electron configuration]
The outermost electronic configuration is
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