Question
A rectangular wire loop of sides 8 cm and 3 cm with a small cut, is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the plane of the loop. The emf developed across the cut, if the velocity of the loop is $2\text{ }cm{\text{ }s}^{- 1}$, in a direction normal to the shorter side of the loop, will be:
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Solution
Sol. [Key Concept: Motional EMF = Bℓv (flux change)] Induced emf across the shorter side
$$\begin{matrix} & E_{\text{induced}\text{~}} = Bvl\lbrack\because\overrightarrow{B}\bot\overrightarrow{V}\bot\overrightarrow{I}\rbrack \\ & \ = 0.3 \times 2 \times 10^{- 2} \times 3 \times 10^{- 2} \\ & \ = 1.8 \times 10^{- 4}\text{ }V \\ & \ = 1.8 \times 10^{- 4}volt \end{matrix}$$
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